12-[4-2(y+1)]=2y+6

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Solution for 12-[4-2(y+1)]=2y+6 equation: 


Simplifying
12 + -1[4 + -2(y + 1)] = 2y + 6

Reorder the terms:
12 + -1[4 + -2(1 + y)] = 2y + 6
12 + -1[4 + (1 * -2 + y * -2)] = 2y + 6
12 + -1[4 + (-2 + -2y)] = 2y + 6

Combine like terms: 4 + -2 = 2
12 + -1[2 + -2y] = 2y + 6
12 + [2 * -1 + -2y * -1] = 2y + 6
12 + [-2 + 2y] = 2y + 6

Combine like terms: 12 + -2 = 10
10 + 2y = 2y + 6

Reorder the terms:
10 + 2y = 6 + 2y

Add '-2y' to each side of the equation.
10 + 2y + -2y = 6 + 2y + -2y

Combine like terms: 2y + -2y = 0
10 + 0 = 6 + 2y + -2y
10 = 6 + 2y + -2y

Combine like terms: 2y + -2y = 0
10 = 6 + 0
10 = 6

Solving
10 = 6

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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